Iowa · Census place 71760
Seymour city, IA
Quick answer
Seymour city has 558 residents, ranking #444 of 1026 places in Iowa. Median household income is $45,000, the median home is worth $78,600 and median gross rent runs $544 a month.
- Population
- 558Seymour city residents
- Median household income
- $45,000Past 12 months, inflation adjusted
- Median home value
- $78,600Owner-occupied units
- Median gross rent
- $544Rent plus utilities, monthly
- Median age
- 51.8 yrsAll residents
- Homeownership rate
- 86%Owner-occupied households
What the numbers mean in Seymour city
Housing cost measured against local earnings.
A household earning the Seymour city median would spend about 14.5% of gross income on the median rent. The 30% mark is the federal threshold for cost burden, so anything above it signals a stretched rental market. The median home costs 1.7× the median household income; nationally that ratio sits near 4.5×. Poverty affects 18.4% of residents and 86% of households own their home.
Source: US Census Bureau, ACS 2019-2023 5-year estimates · rates as published for 2019-2023 ACS 5-year
Compare with nearby places
Places of similar size in Iowa.
- Rudd city 568
- Richland city 566
- Cumming city 558
- Lynnville city 557
- Garwin city 554
- Grand Mound city 554
- Russell city 551
Keep going
More Iowa coverage.