Indiana · Census place 68832
Seymour city, IN
Quick answer
Seymour city has 21,536 residents, ranking #48 of 976 places in Indiana. Median household income is $63,388, the median home is worth $153,300 and median gross rent runs $954 a month.
- Population
- 21,536Seymour city residents
- Median household income
- $63,388Past 12 months, inflation adjusted
- Median home value
- $153,300Owner-occupied units
- Median gross rent
- $954Rent plus utilities, monthly
- Median age
- 33.3 yrsAll residents
- Homeownership rate
- 57.1%Owner-occupied households
What the numbers mean in Seymour city
Housing cost measured against local earnings.
A household earning the Seymour city median would spend about 18.1% of gross income on the median rent. The 30% mark is the federal threshold for cost burden, so anything above it signals a stretched rental market. The median home costs 2.4× the median household income; nationally that ratio sits near 4.5×. Poverty affects 14.4% of residents and 57.1% of households own their home.
Source: US Census Bureau, ACS 2019-2023 5-year estimates · rates as published for 2019-2023 ACS 5-year
Compare with nearby places
Places of similar size in Indiana.
- La Porte city 22,125
- Clarksville town 22,121
- St. John town 21,639
- Shelbyville city 19,866
- Logansport city 17,766
- Lebanon city 17,575
- New Castle city 17,356
Keep going
More Indiana coverage.