Seward ZIP codes — Seward County, Nebraska

Seward County is a mid-size town in Nebraska, with 17,636 residents counted in the Census American Community Survey 2019-2023 ACS 5-year estimates. The median age here is 37.6 years against 39.1 nationally, a slightly younger profile than the country as a whole. Places under 65,000 residents only appear in the five-year release, never the one-year file, so these values pool sixty months of responses and lag the current year by design.

Households in Seward County earn a median of $81,122 a year, 3.3% above the national figure of $78,538. The median is the midpoint household, not an average, so a handful of very high earners cannot drag it upward the way they distort a mean. Poverty reaches 6.9% of residents here, below the 12.4% national rate.

The typical owner-occupied home in Seward County is valued at $232,400, 23.4% below the national figure, while median gross rent runs $969 a month, 31.1% below the national figure, or roughly $11,628 across a full year. A household on the local median income would put about 14.3% of gross pay toward that rent against the federal 30% cost-burden threshold, so renting here is cheap relative to what people here earn. The home-price-to-income ratio works out to 2.9×, against roughly 3.9× nationally, so buying is easier here than in the average US market. 72.1% of occupied homes are owner-occupied versus 65% nationally, so the market leans toward owners. Rent is reported gross — contract rent plus tenant-paid utilities — which is why it runs above the advertised price on a listing for the same unit.

No figure on this page is estimated by us; each one comes straight from the published ACS tables for this area. Small-area estimates still carry wider margins of error than state or national figures, so check the linked ACS tables before relying on them for lending, appraisal or legal work.